How to create a Rhino Common Object from a Guid

[Martin]

Hi,

If I use the rs.GetObject("Get Object") to select for example a curve I get the Guid of the curve as a return value.

Now I would like to create a NurbsCurve Object from that Guid (Rhino.Geometry.NurbsCurve())

So I can delete the object from the scene, but later can access the data again, if I need it.

How do I do that?

Thanks for your help.
Martin

[Martin]

Hi,

well I found a Solution.

Python Code:

#Get the Cuve
   guid = rs.GetObject("Get Curve")
   
   #Get the Instance of the currently active Rhino Document
   doc = Rhino.RhinoDoc.ActiveDoc
   
   #Get the Object from the current Active Doc
   object = doc.Objects.Find(guid)
   
   #Delete the Original Object
   rs.DeleteObject(guid)
   
   #Get CurveGeometry From Object
   crv = object.CurveGeometry
   
   #Create the Curve again (with a new ID)
   newObject = doc.Objects.AddCurve(crv)

The only thing missing is a "isCurve" Command in Rhino Common. It's probably somewhere, but I couldn't find it.

Thanks
Martin

[marian]

how about: if object.ObjectType == Rhino.DocObjects.ObjectType.Curve

[Martin]

Thanks Marian,
sounds good.

-
Martin

[Steve Baer]

Hi Martin,
I would recommend changing this just a wee bit:

Python Code:

import rhinoscriptsyntax as rs
import scriptcontext
 
#Get the Cuve
guid = rs.GetObject("Get Curve", rs.filter.curve)
 
#Get the Instance of the document that ran this script. This is always the
#same as Rhino.RhinoDoc.ActiveDoc on Windows, but on Mac this may not
#be the case
doc = scriptcontext.doc
   
#Get the Object from the current Active Doc
object = doc.Objects.Find(guid)
#Get the curve geometry from the object
crv = object.CurveGeometry
# make absolutely sure that the curve is a "private" copy
# and is not still under the control of the RhinoDoc
crv.EnsurePrivateCopy()
#Now delete the Original Object
rs.DeleteObject(guid)
 
# ...do some things...
#Create the Curve again (with a new ID)
newObject = doc.Objects.AddCurve(crv)

[Martin]

Thanks Steve,

works great.

-
Martin